Verilog Blocking & Non-Blocking
Blocking assignment statements are assigned using = and are executed one after the other in a procedural block. However, this will not prevent execution of statments that run in a parallel block.
Note that there are two initial blocks which are executed in parallel when simulation starts. Statements are executed sequentially in each block and both blocks finish at time 0ns. To be more specific, variable a gets assigned first, followed by the display statement which is then followed by all other statements. This is visible in the output where variable b and c are 8'hxx in the first display statement. This is because variable b and c assignments have not been executed yet when the first $display is called.
In the next example, we'll add a few delays into the same set of statements to see how it behaves.
Non-blocking
Non-blocking assignment allows assignments to be scheduled without blocking the execution of following statements and is specified by a symbol. It's interesting to note that the same symbol is used as a relational operator in expressions, and as an assignment operator in the context of a non-blocking assignment. If we take the first example from above, replace all = symobls with a non-blocking assignment operator , we'll see some difference in the output.
See that all the $display statements printed 'h'x . The reason for this behavior lies in the way non-blocking assignments are executed. The RHS of every non-blocking statement of a particular time-step is captured, and moves onto the next statement. The captured RHS value is assigned to the LHS variable only at the end of the time-step.
So, if we break down the execution flow of the above example we'll get something like what's shown below.
Next, let's use the second example and replace all blocking statements into non-blocking.
Once again we can see that the output is different than what we got before.
If we break down the execution flow we'll get something like what's shown below.
IMAGES
VIDEO
COMMENTS
There are three basic forms: Procedural. Continuous. Procedural continuous. Legal LHS values. An assignment has two parts - right-hand side (RHS) and left-hand side (LHS) with an equal symbol (=) or a less than-equal symbol (<=) in between.
you can use left-hand concats. The following example shows how to do it. reg a,b,c,d,e; initial begin. {a,b,c,d,e} = 5'b0; end. there is no other more 'condenced' way, unless you use an array. reg [4:0] var;
The module shown below takes two inputs and uses an assign statement to drive the output z using part-select and multiple bit concatenations. Treat each case as the only code in the module, else many assign statements on the same signal will definitely make the output become X.
Explore the Verilog Assign statement, its applications in combinational logic and more; with practical examples ranging from AND gates to complex modules.
In VHDL, when you have multiple assignments to a signal within a process (i.e. an always block), whether it's sequential or combinatorial, the signal assignment that's written last in the code will take precedence.
Blocking assignment statements are assigned using = and are executed one after the other in a procedural block. However, this will not prevent execution of statments that run in a parallel block.
assign var_inst0 = dut.module1.module2.reg_cfg[0].var; assign var_inst1 = dut.module1.module2.reg_cfg[1].var; and so on. Is there a way to write a for loop to assign all these variables at once instead of writing 100 assign statements.
The explicit assignment require two statements: one to declare the net (see Net data type), and one to continuously assign a value to it.
Given two separate always @( posedge clk ) block in the same module, what happens if I assign two different values in each of them respectively to the same register? I guess the question is in ge...
Advanced Verilog EECS 270 v10/23/06 Continuous Assignments review • Continuously assigns right side of expression to left side. • Limited to basic Boolean and ? operators. For example a 2:1 mux: – ? operator assign D = (A= =1) ? B : C; // if A then D = B else D = C; – Boolean operators assign D = (B & A) | (C & ~A); // if A then D = B ...