(iv) The objects is not a square
(v) The objects is a circle
(vi) The objects is a square
(a) 5/16
(b) 4/16
(c) 7/16
(d) 9/16
(e) 12/16
(f) 11/16
Number of blue triangles in a container = 4
Number of green squares = 5
Number of red circles = 7
Total number of objects = 4 + 5 + 7 = 16
(i) The objects is not a circle:
P(the object is a circle)
= Number of circles/Total number of objects
P(the object is not a circle)
= 1 - P(the object is a circle)
= (16 - 7)/16
(ii) The objects is a triangle:
P(the object is a triangle)
= Number of triangle/Total number of objects
(iii) The objects is not a triangle:
= Number of triangles/Total number of objects
P(the object is not a triangle)
= 1 - P(the object is a triangle)
= (16 - 4)/16
(iv) The objects is not a square:
P(the object is a square)
= Number of squares/Total number of objects
P(the object is not a square)
= 1 - P(the object is a square)
= (16 - 5)/16
(v) The objects is a circle:
(vi) The objects is a square:
Match the following events with the corresponding probabilities are shown below:
(i) The objects is not a circle (ii) The objects is a triangle (iii) The objects is not a triangle (iv) The objects is not a square (v) The objects is a circle (vi) The objects is a square | 9/16 4/16 12/16 11/16 7/16 5/16 |
2. A single card is drawn at random from a standard deck of 52 playing cards.
Match each event with its probability.
Note: fractional probabilities have been reduced to lowest terms. Consider the ace as the highest card.
(i) The card is a diamond (ii) The card is a red king (iii) The card is a king or queen (iv) The card is either a red or an ace (v) The card is not a king (vi) The card is a five or lower (vii) The card is a king (viii) The card is black | (a) 1/2 (b) 1/13 (c) 1/26 (d) 12/13 (e) 2/13 (f) 1/4 (g) 4/13 (h) 7/13 |
Total number of playing cards = 52
(i) The card is a diamond:
Number of diamonds in a deck of 52 cards = 13
P(the card is a diamond)
= Number of diamonds/Total number of playing cards
(ii) The card is a red king:
Number of red king in a deck of 52 cards = 2
P(the card is a red king)
= Number of red kings/Total number of playing cards
(iii) The card is a king or queen:
Number of kings in a deck of 52 cards = 4
Number of queens in a deck of 52 cards = 4
Total number of king or queen in a deck of 52 cards = 4 + 4 = 8
P(the card is a king or queen)
= Number of king or queen/Total number of playing cards
(iv) The card is either a red card or an ace:
Total number of red card or an ace in a deck of 52 cards = 28
P(the card is either a red card or an ace)
= Number of cards which is either a red card or an ace/Total number of playing cards
(v) The card is not a king:
P(the card is a king)
= Number of kings/Total number of playing cards
P(the card is not a king)
= 1 - P(the card is a king)
= (13 - 1)/13
(vi) The card is a five or lower:
Number of cards is a five or lower = 16
P(the card is a five or lower)
= Number of card is a five or lower/Total number of playing cards
(vii) The card is a king:
(viii) The card is black:
Number of black cards in a deck of 52 cards = 26
P(the card is black)
= Number of black cards/Total number of playing cards
(i) The card is a diamond (ii) The card is a red king
(iii) The card is a king or queen (iv) The card is either a red or an ace (v) The card is not a king (vi) The card is a five or lower (vii) The card is a king | 1/4 1/26 2/13 7/13
12/13 4/13 1/13
|
3. A bag contains 3 red balls and 4 black balls. A ball is drawn at random from the bag. Find the probability that the ball drawn is
(ii) not black.
(i) Total number of possible outcomes = 3 + 4 = 7.
Number of favourable outcomes for the event E.
= Number of black balls = 4.
So, P(E) = \(\frac{\textrm{Number of Favourable Outcomes for the Event E}}{\textrm{Total Number of Possible Outcomes}}\)
= \(\frac{4}{7}\).
(ii) The event of the ball being not black = \(\bar{E}\).
Hence, required probability = P(\(\bar{E}\))
= 1 - P(E)
= 1 - \(\frac{4}{7}\)
= \(\frac{3}{7}\).
4. If the probability of Serena Williams a particular tennis match is 0.86, what is the probability of her losing the match?
Let E = the event of Serena Williams winning.
From the question, P(E) = 0.86.
Clearly, \(\bar{E}\) = the event of Serena Williams losing.
So, P(\(\bar{E}\)) = 1 - P(E)
= 1 - 0.86
= 0.14
= \(\frac{14}{100}\)
= \(\frac{7}{50}\).
5. Find the probability of getting 53 Sunday in a leap year.
A leap year has 366 days. So, it has 52 weeks and 2 days.
So, 52 Sundays are assured. For 53 Sundays, one of the two remaining days must be a Sunday.
For the remaining 2 days we can have
(Sunday, Monday), (Monday, Tuesday), (Tuesday, Wednesday), (Wednesday, Thursday), (Thursday, Friday), (Friday, Saturday), (Saturday, Sunday).
So, total number of possible outcomes = 7.
Number of favourable outcomes for the event E = 2, [namely, (Sunday, Monday), (Saturday, Sunday)].
So, by definition: P(E) = \(\frac{2}{7}\).
6. A lot of 24 bulbs contains 25% defective bulbs. A bulb is drawn at random from the lot. It is found to be not defective and it is not put back. Now, one bulb is drawn at random from the rest. What is the probability that this bulb is not defective?
25% of 24 = \(\frac{25}{100}\) × 24 = 6.
So, there are 6 defective bulbs and 18 bulbs are not defective.
After the first draw, the lot is left with 6 defective bulbs and 17 non-defective bulbs.
So, when the second bulb is drwn, the total number of possible outcomes = 23 (= 6+ 17).
Number of favourable outcomes for the event E = number of non-defective bulbs = 17.
So, the required probability = P(E) = (\frac{17}{23}\).
The examples can help the students to practice more questions on probability by following the concept provided in the solved probability problems.
Random Experiments
Experimental Probability
Events in Probability
Empirical Probability
Coin Toss Probability
Probability of Tossing Two Coins
Probability of Tossing Three Coins
Complimentary Events
Mutually Exclusive Events
Mutually Non-Exclusive Events
Conditional Probability
Theoretical Probability
Odds and Probability
Playing Cards Probability
Probability and Playing Cards
Probability for Rolling Two Dice
Probability for Rolling Three Dice
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About this unit.
Probability tells us how often some event will happen after many repeated trials. You've experienced probability when you've flipped a coin, rolled some dice, or looked at a weather forecast. Go deeper with your understanding of probability as you learn about theoretical, experimental, and compound probability, and investigate permutations, combinations, and more!
Related Topics & Worksheets: Probability Worksheet 2 Complementary Probability Worksheet
Objective: I know how to solve probability word problems.
The following are more probability problems for you to practice.
Read the lesson on probability problems for more information and examples.
Work out the following. When necessary, give your answer in fractions eg. 2/5
We hope that the free math worksheets have been helpful. We encourage parents and teachers to select the topics according to the needs of the child. For more difficult questions, the child may be encouraged to work out the problem on a piece of paper before entering the solution. We hope that the kids will also love the fun stuff and puzzles.
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How likely something is to happen.
Many events can't be predicted with total certainty. The best we can say is how likely they are to happen, using the idea of probability.
When a coin is tossed, there are two possible outcomes:
Heads (H) or Tails (T)
When a single die is thrown, there are six possible outcomes: 1, 2, 3, 4, 5, 6 .
The probability of any one of them is 1 6
In general:
Probability of an event happening = Number of ways it can happen Total number of outcomes
Number of ways it can happen: 1 (there is only 1 face with a "4" on it)
Total number of outcomes: 6 (there are 6 faces altogether)
So the probability = 1 6
Number of ways it can happen: 4 (there are 4 blues)
Total number of outcomes: 5 (there are 5 marbles in total)
So the probability = 4 5 = 0.8
We can show probability on a Probability Line :
Probability is always between 0 and 1
Probability does not tell us exactly what will happen, it is just a guide
Probability says that heads have a ½ chance, so we can expect 50 Heads .
But when we actually try it we might get 48 heads, or 55 heads ... or anything really, but in most cases it will be a number near 50.
Learn more at Probability Index .
Some words have special meaning in Probability:
Experiment : a repeatable procedure with a set of possible results.
We can throw the dice again and again, so it is repeatable.
The set of possible results from any single throw is {1, 2, 3, 4, 5, 6}
Outcome: A possible result.
Trial: A single performance of an experiment.
Trial | Trial | Trial | Trial | |
---|---|---|---|---|
Head | ✔ | ✔ | ✔ | |
Tail | ✔ |
Three trials had the outcome "Head", and one trial had the outcome "Tail"
Sample Space: all the possible outcomes of an experiment.
There are 52 cards in a deck (not including Jokers)
So the Sample Space is all 52 possible cards : {Ace of Hearts, 2 of Hearts, etc... }
The Sample Space is made up of Sample Points:
Sample Point: just one of the possible outcomes
"King" is not a sample point. There are 4 Kings, so that is 4 different sample points.
There are 6 different sample points in that sample space.
Event: one or more outcomes of an experiment
An event can be just one outcome:
An event can include more than one outcome:
Hey, let's use those words, so you get used to them:
The Sample Space is all possible Outcomes (36 Sample Points):
{1,1} {1,2} {1,3} {1,4} ... ... ... {6,3} {6,4} {6,5} {6,6}
The Event Alex is looking for is a "double", where both dice have the same number. It is made up of these 6 Sample Points :
{1,1} {2,2} {3,3} {4,4} {5,5} and {6,6}
These are Alex's Results:
Trial | Is it a Double? |
---|---|
{3,4} | No |
{5,1} | No |
{2,2} | |
{6,3} | No |
... | ... |
After 100 Trials , Alex has 19 "double" Events ... is that close to what you would expect?
Hey mathematicians! My name's Ms Szalek and welcome to maths. Today we're going to focus on probability.
For this lesson, you'll need a pencil, paper, a die, and a coin.
First, let's get into our warm up. I'm going to be flipping a coin, so I'd love you to get a coin and flip along with me. Now, if you look at our coin, we have heads and we have tails. That means we have two possible outcomes. I'm going to be flipping my coin four times and I'd love you to flip along. Are you ready? Okay, here we go. Let's see what we get.
Heads. How did you go? I got heads again. What did you get? Oh, tails. Okay our last one. Whoa, tails. So I got two heads and two tails. How did you go at home? Do you think if we did this again, we would get two heads and two tails every time? Well, let's get into today's lesson and find out.
Our learning intention for today is to determine and represent probabilities of equally likely events as fractions.
But first, what is probability? Well, probability is the likelihood or chance that an event can occur. What are some of the words we already know about probability? Let's take a look together. We have impossible, unlikely, equally likely, likely, and certain. So impossible, what does that mean? Well, that means something is impossible. The event cannot happen. There is no chance. It is definitely not going to happen. On the other end of the scale we have certain which means that our event is certain. It is absolutely definitely going to happen. When we look into the middle, we can see equally likely. And when we think about it like a scale, there is an equal chance that it will either happen or not happen. Then, when we see likely we're closer to certain, which means there's more of a chance that it will happen. And unlikely being closer to impossible means that there is less of a chance of our event occurring.
But what do these look like when we write them as fractions? If we look at impossible, well, we already said that there was a zero chance that our event can occur. Which means that impossible is zero.
When we look at equally likely, well, just like when we looked with our coin, we had heads and we had tails. That's right. So out of our total outcomes, we had heads and tails. We had two outcomes. That means our denominator is two. Two represents our total outcomes. When we flip our coin, we can only land on either a head or a tail. We can't land on both, which means that we have a one out of two chance of getting a head and a one out of two chance of getting a tail. So equally likely comes down as one half. So we have a half chance of our event happening and a half chance of it not happening.
When we look at certain, well, we know that it is absolutely going to happen. So out of two, it means that we have a two out of two chance that our event's going to occur. And we know that two halves make a whole, so certain is actually the same as one whole. So our scale of probability goes from zero at impossible to one, certain.
When we're looking at our likely and unlikely, well, we're halfway between a half and a whole, and halfway between a half and a whole is actually three quarters, as we can see here. And when we move to unlikely, well, that's halfway between zero and a half, which means that we have one quarter. And this is how we represent probability using fractions.
What will these fractions look like if we put them into action? Well, let's do an activity now. I've got a coin here and I'm going to flip it eight times. I'd love for you to get a coin and flip along with me at home. Before we start, let's look at what we might expect to happen. Well, I've got a head on one side and a tail on the other. So every time I flip the coin, two times I would expect that one of them would be a head and the other would be a tail. Do you think that's actually what's going to happen though? Well, let's find out together.
Heads. Heads again. Are you ready? What did you get at home? Whoa, I got heads again. Do you think the next one's going to be a head? Well, that might not be the case because chance has no memory. So our probability resets each time. So for every flip, there's still a one in two chance that I will get a head or a tail. Oh, look at that, I got tails. Heads. Tails. Tails. Heads.
Now we're going to look at our actual outcomes. Our actual outcomes are out of eight because we flipped the coin eight times. How many heads did you get out of your eight flips? Well, I got one, two, three, four, five. So I'm going to write five out of eight, which means that my actual outcome was five eighths. How many tails did you get? Well, as you can see, I got one, two, three, so I got three tails. So I'm going to do three out of eight. Now, that's not quite what we expected because we know that four eighths are a half and I didn't get four eighths on either of my flips, which means that our actual outcomes are not always the same as our expected outcomes. They can be different. What if we have more possible outcomes? What if we had say six? What if instead of flipping a coin, we rolled a die.
With a die, we know that there are six sides and on each side is a different number. That means that our total number of outcomes is six. Our probability of rolling, say, a four, that would be one in, you guessed it, that would be one in six. My favourite number is three. Do you think that I'd have a higher probability of rolling a three? Well, that's not actually the case because probability doesn't take into account our favourites. Remember that probability is the likelihood or chance that an event can occur. Let's roll and find out. Whoa, I rolled a four, but I want to see how many times I can roll a three, cause remember it is my favourite. And let's look at the board. If I want to roll a three, I expect to roll it one out of every six times. So let's roll it five more times and see how we go. Another four. And a two. And another four. Two more rolls here. Another two and one more, a six. So we didn't even roll a three out of our six trials. That means that our expected outcome is not the same as our actual outcome. What do you think might happen if we rolled it 50 or a hundred or a thousand or even a million times? Well, in the long run, our actual outcomes would get closer and closer to our expected outcomes.
Now it's your turn to try at home. Grab a die and choose a number between one and six. Try to work out what your expected probability is, and then describe it using a fraction. Then the challenge is to roll your die 12, 24 or even 50 times, and see if your actual outcome matches the expected probability that you wrote before. Thanks for joining me today to learn how we can use fractions to describe probability. My name's Ms Szalek. Have a great day.
SUBJECTS: Maths
YEARS: 5–6
Ms Szalek explains some of the words used in probability, and then she suggests how you can investigate using fractions to find expected and actual outcomes in an experiment.
Special thanks to Ms Szalek, The Victorian Department of Education and Training, and Hillsmeade Primary School.
Production Date: 2021
Metadata © Australian Broadcasting Corporation 2020 (except where otherwise indicated). Digital content © Australian Broadcasting Corporation (except where otherwise indicated). Video © Australian Broadcasting Corporation and Department of Education and Training (Victoria). All images copyright their respective owners. Text © Australian Broadcasting Corporation and Department of Education and Training (Victoria).
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Beki Christian
Probability questions and probability problems require students to work out how likely it is that something is to happen. Probabilities can be described using words or numbers. Probabilities range from 0 to 1 and can be written as fractions, decimals or percentages .
Here you’ll find a selection of probability questions of varying difficulty showing the variety you are likely to encounter in middle school and high school, including several harder exam style questions.
The more likely something is to happen, the higher its probability. We think about probabilities all the time.
For example, you may have seen that there is a 20% chance of rain on a certain day or thought about how likely you are to roll a 6 when playing a game, or to win in a raffle when you buy a ticket.
Summer Math Activities
Looking for math games and activities for the final weeks before summer or something to share with your students over the break? Keep math a focus and transition into the next grade with 4 separate worksheets for each grade including relevant topic-based games!
The probability of something happening is given by:
We can also use the following formula to help us calculate probabilities and solve problems:
Question: What is the probability of getting heads three times in a row when flipping a coin?
When flipping a coin, there are two possible outcomes – heads or tails. Each of these options has the same probability of occurring during each flip. The probability of either heads or tails on a single coin flip is ½.
Since there are only two possible outcomes and they have the same probability of occurring, this is called a binomial distribution.
Let’s look at the possible outcomes if we flipped a coin three times.
Let H=heads and T=tails.
The possible outcomes are: HHH, THH, THT, HTT, HHT, HTH, TTH, TTT
Each of these outcomes has a probability of ⅛.
Therefore, the probability of flipping a coin three times in a row and having it land on heads all three times is ⅛.
In middle school, probability questions introduce the idea of the probability scale and the fact that probabilities sum to one. We look at theoretical and experimental probability as well as learning about sample space diagrams and venn diagrams.
1. Which number could be added to this spinner to make it more likely that the spinner will land on an odd number than a prime number?
Currently there are two odd numbers and two prime numbers so the chances of landing on an odd number or a prime number are the same. By adding 3, 5 or 11 you would be adding one prime number and one odd number so the chances would remain equal.
By adding 9 you would be adding an odd number but not a prime number. There would be three odd numbers and two prime numbers so the spinner would be more likely to land on an odd number than a prime number.
2. Ifan rolls a fair dice, with sides labeled A, B, C, D, E and F. What is the probability that the dice lands on a vowel?
A and E are vowels so there are 2 outcomes that are vowels out of 6 outcomes altogether.
Therefore the probability is \frac{2}{6} which can be simplified to \frac{1}{3} .
3. Max tested a coin to see whether it was fair. The table shows the results of his coin toss experiment:
Heads Tails
26 41
What is the relative frequency of the coin landing on heads?
Max tossed the coin 67 times and it landed on heads 26 times.
\text{Relative frequency (experimental probability) } = \frac{\text{number of successful trials}}{\text{total number of trials}} = \frac{26}{67}
4. Grace rolled two dice. She then did something with the two numbers shown. Here is a sample space diagram showing all the possible outcomes:
What did Grace do with the two numbers shown on the dice?
Add them together
Subtract the number on dice 2 from the number on dice 1
Multiply them
Subtract the smaller number from the bigger number
For each pair of numbers, Grace subtracted the smaller number from the bigger number.
For example, if she rolled a 2 and a 5, she did 5 − 2 = 3.
5. Alice has some red balls and some black balls in a bag. Altogether she has 25 balls. Alice picks one ball from the bag. The probability that Alice picks a red ball is x and the probability that Alice picks a black ball is 4x. Work out how many black balls are in the bag.
Since the probability of mutually exclusive events add to 1:
\begin{aligned} x+4x&=1\\\\ 5x&=1\\\\ x&=\frac{1}{5} \end{aligned}
\frac{1}{5} of the balls are red and \frac{4}{5} of the balls are blue.
6. Arthur asked the students in his class whether they like math and whether they like science. He recorded his results in the venn diagram below.
How many students don’t like science?
We need to look at the numbers that are not in the ‘Like science’ circle. In this case it is 9 + 7 = 16.
In high school, probability questions involve more problem solving to make predictions about the probability of an event. We also learn about probability tree diagrams, which can be used to represent multiple events, and conditional probability.
7. A restaurant offers the following options:
Starter – soup or salad
Main – chicken, fish or vegetarian
Dessert – ice cream or cake
How many possible different combinations of starter, main and dessert are there?
The number of different combinations is 2 × 3 × 2 = 12.
8. There are 18 girls and 12 boys in a class. \frac{2}{9} of the girls and \frac{1}{4} of the boys walk to school. One of the students who walks to school is chosen at random. Find the probability that the student is a boy.
First we need to work out how many students walk to school:
\frac{2}{9} \text{ of } 18 = 4
\frac{1}{4} \text{ of } 12 = 3
7 students walk to school. 4 are girls and 3 are boys. So the probability the student is a boy is \frac{3}{7} .
9. Rachel flips a biased coin. The probability that she gets two heads is 0.16. What is the probability that she gets two tails?
We have been given the probability of getting two heads. We need to calculate the probability of getting a head on each flip.
Let’s call the probability of getting a head p.
The probability p, of getting a head AND getting another head is 0.16.
Therefore to find p:
The probability of getting a head is 0.4 so the probability of getting a tail is 0.6.
The probability of getting two tails is 0.6 × 0.6 = 0.36 .
10. I have a big tub of jelly beans. The probability of picking each different color of jelly bean is shown below:
If I were to pick 60 jelly beans from the tub, how many orange jelly beans would I expect to pick?
First we need to calculate the probability of picking an orange. Probabilities sum to 1 so 1 − (0.2 + 0.15 + 0.1 + 0.3) = 0.25.
The probability of picking an orange is 0.25.
The number of times I would expect to pick an orange jelly bean is 0.25 × 60 = 15 .
11. Dexter runs a game at a fair. To play the game, you must roll a dice and pick a card from a deck of cards.
To win the game you must roll an odd number and pick a picture card. The game can be represented by the tree diagram below.
Dexter charges players $1 to play and gives $3 to any winners. If 260 people play the game, how much profit would Dexter expect to make?
Completing the tree diagram:
Probability of winning is \frac{1}{2} \times \frac{4}{13} = \frac{4}{26}
If 260 play the game, Dexter would receive $260.
The expected number of winners would be \frac{4}{26} \times 260 = 40
Dexter would need to give away 40 × $3 = $120 .
Therefore Dexter’s profit would be $260 − $120 = $140.
12. A fair coin is tossed three times. Work out the probability of getting two heads and one tail.
There are three ways of getting two heads and one tail: HHT, HTH or THH.
The probability of each is \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{8}
Therefore the total probability is \frac{1}{8} +\frac{1}{8} + \frac{1}{8} = \frac{3}{8}
13. 200 people were asked about which athletic event they thought was the most exciting to watch. The results are shown in the table below.
A person is chosen at random. Given that that person chose 100m, what is the probability that the person was female?
Since we know that the person chose 100m, we need to include the people in that column only.
In total 88 people chose 100m so the probability the person was female is \frac{32}{88} .
14. Sam asked 50 people whether they like vegetable pizza or pepperoni pizza.
37 people like vegetable pizza.
25 people like both.
3 people like neither.
Sam picked one of the 50 people at random. Given that the person he chose likes pepperoni pizza, find the probability that they don’t like vegetable pizza.
We need to draw a venn diagram to work this out.
We start by putting the 25 who like both in the middle section. The 37 people who like vegetable pizza includes the 25 who like both, so 12 more people must like vegetable pizza. 3 don’t like either. We have 50 – 12 – 25 – 3 = 10 people left so this is the number that must like only pepperoni.
There are 35 people altogether who like pepperoni pizza. Of these, 10 do not like vegetable pizza. The probability is \frac{10}{35} .
15. There are 12 marbles in a bag. There are n red marbles and the rest are blue marbles. Nico takes 2 marbles from the bag. Write an expression involving n for the probability that Nico takes one red marble and one blue marble.
We need to think about this using a tree diagram. If there are 12 marbles altogether and n are red then 12-n are blue.
To get one red and one blue, Nico could choose red then blue or blue then red so the probability is:
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The content in this article was originally written by secondary teacher Beki Christian and has since been revised and adapted for US schools by elementary math teacher Katie Keeton.
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Year levels.
Australian Curriculum Mathematics V9 : AC9M5P02
Numeracy Progression : Understanding chance: P3 and P4
At this level, students conduct repeated chance experiments including those with and without equally likely outcomes. They then observe the outcome of their chance experiments, record data and describe the relative frequencies.
Provide opportunities for students to collaboratively conduct repeated chance experiments that have equally likely outcomes. Students can use physical materials or virtual random generators to investigate the probabilities of tossing a coin, rolling a dice or spinning a spinner with equal segments using a small number of trials. They can then compare these to chance experiments that do not have equally likely outcomes, for example, a spinner with larger sections of one colour compared to the rest or a bag containing unequal numbers of coloured marbles.
Present problem-solving challenges to students, and, where possible, use simulations to model probabilities as well as questioning students to prompt them to draw on their reasoning skills.
Look for opportunities for students to use spreadsheets to record data of chance experiments and then present the data to inform analysis and interpretation of the results. Results can be used in automated calculations of total frequency.
There is an opportunity to make connections to statistics, plan and conduct statistical investigations (AC9M5ST03).
Teaching and learning summary:
Some students may:
To address these misconceptions, ask students to conduct repeated chance experiments, recording and interpreting the results.
The Learning from home activities are designed to be used flexibly by teachers, parents and carers, as well as the students themselves. They can be used in a number of ways including to consolidate and extend learning done at school or for home schooling.
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Teaching strategies.
A collection of evidence-based teaching strategies applicable to this topic. Note we have not included an exhaustive list and acknowledge that some strategies such as differentiation apply to all topics. The selected teaching strategies are suggested as particularly relevant, however you may decide to include other strategies as well.
Explicit teaching is about making the learning intentions and success criteria clear, with the teacher using examples and working though problems, setting relevant learning tasks and checking student understanding and providing feedback.
By giving students meaningful problems to solve they are engaged and can apply their learning, thereby deepening their understanding.
A culture of questioning should be encouraged and students should be comfortable to ask for clarification when they do not understand.
Differentiation involves teachers creating lessons that are accessible and challenging for all students.
It has been shown that good feedback can make a significant difference to a student’s future performance.
For group work to be effective students need to be taught explicitly how to work together in different settings, such as pairs or larger groups, and they need to practise these skills.
Providing students with multiple opportunities within different contexts to practise skills and apply concepts allows them to consolidate and deepen their understanding.
A range of resources to support you to build your student's understanding of these concepts, their skills and procedures. The resources incorporate a variety of teaching strategies.
In this task, students use a digital tool to test their predictions of the colours of marbles in a bag, based on data from 10 trials.
In this task, students use a random generator to compare real data of 20 trials of a coin toss to made-up data.
This problem offers students the opportunity to get a feel for experimental probability and work systematically to find all possible outcomes.
Use this dynamic software, which is a random generator for a die roll and includes data represented as a histogram and larger trials, to explore chance and probability.
Use this task to conduct a chance experiment to work out the probability of rolling totals using two dice.
Use this task to ask students to apply their understanding of probability and possible outcomes and to practise addition and subtraction.
The purpose of this activity is to engage students in running an experiment to determine a probability and compare this with the results of similar practical situations.
Relevant assessment tasks and advice related to this topic.
By the end of Year 5, students are conducting repeated chance experiments, listing the possible outcomes, estimating likelihoods and making comparisons between those with and without equally likely outcomes.
Use this task to assess students’ understanding of probability.
Refer to ACARA work sample 11, 'Come in spinner', to assess students’ understanding of probability through the task. Students list outcomes of chance experiments with equally likely outcomes and assign probabilities as a number from zero to one.
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Take a look at our decimal place value sheets, our mental math sheets, or maybe some of our equivalent fraction worksheets. Perhaps you would prefer our statistics worksheets, or how to measure angles?
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Our site is mainly based around the US Elementary school math standards.
Though the links on this page are all designed primarily for students in the US, but they are also at the correct level and standard for UK students.
The main issue is that some of the spelling is different and this site uses US spelling.
Year 5 is generally equivalent to 4th Grade in the US.
On this page you will find link to our range of math worksheets for Year 5.
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For those parents who have found themselves unexpectedly at home with the kids and need some emergency activities for them to do, we have started to develop some Maths Grab Packs for kids in the UK.
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Year 5 place value worksheets.
Using these Year 5 maths worksheets will help your child to:
Using these Year 5 Maths worksheets will help your child to:
Using these sheets will support you child to:
Here you will find a range of printable Year 5 mental maths sheets for your child to enjoy.
Each quiz tests the children on a range of maths topics from number facts and mental arithmetic to geometry, fraction and measures questions.
A great way to revise topics, or use as a weekly math test or math quiz!
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Using these 4th grade math worksheets will help your child to:
Using these Year 5 maths worksheets will help your child learn to:
These sheets involve solving a range of division problems.
Using the problems in this section will help your child develop their problem solving and reasoning skills.
These sheets involve solving one or two more challenging longer problems.
These sheets involve solving many 'real-life' problems involving data.
These sheets involve solving a range of multiplciation problems.
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Year 5 fraction worksheets.
Take a look at our percentage worksheets for finding the percentage of a number or money amount.
We have a range of percentage sheets from quite a basic level to much harder.
Using these sheets will help you to:
Year 5 measurement worksheets.
Using these sheets will help your child understand how to:
Using the sheets in this section will help your child to:
On this webpage there is a selection of printable 24 hour (military time) conversion worksheets which will help you learn to convert from 24 hour clock to standard 12 hour time, and from standard time to 24 hour time.
These sheets will help you learn to add and subtract hours and minutes from times as well as working out a range of time intervals.
Here you will find our selection of harder time puzzles.
Using these 4th grade math worksheets will help you to:
Year 5 maths games.
The puzzles will help your child practice and apply their addition, subtraction, multiplication and division facts as well as developing their thinking and reasoning skills in a fun and engaging way.
Our Year 5 Maths Games Ebook contains all of our fun maths games, complete with instructions and resources.
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Probability is a way of measuring, like length or area or weight or height. It measures the chance of a particular outcome occurring.
You might have considered simple and familiar outcomes involving chance and described whether they are 'likely' or 'unlikely', with some being 'certain' or 'impossible'.
We can compare probabilities on a scale using words like 'impossible' and 'certain' at each end of the scale, and words like 'not very likely', 'likely' and 'highly likely' to describe outcomes somewhere in between. For example, the chance of the Prime Minister walking into your classroom in the next five minutes is not very likely, but it is not impossible.
In the following pages we look at chance experiments, and describe the chance of particular events occurring using a number between 0 and 1.
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Subject: Mathematics
Age range: 7-11
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10 September 2014
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I used this sheet for my lower ability year 9 group as a starter task. I wanted them to revise the topic, but also remind them how simple probability can be if they read the questions properly. The wording was straight forward and sufficiently challenging for their poor literacy skills. This proved to be a great task, and had all my students engaged.
Worded problems with good diagrams are hard to find. Nice work.
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A set of 20 problem solving questions suited to year 5 students.
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This set of problem-solving questions has been designed to support teachers when teaching students about problem-solving in mathematics. It provides students with the opportunity to work through 20 maths word problems, identifying the important information and how they can work it out using a variety of methods.
An answer sheet has been included. Use this resource in conjunction with the Daily Maths Problems PowerPoint.
These simple problem-solving questions are also a great way to help students understand some of the word problems they may encounter when sitting NAPLAN. It’s important to give your students strategies that they can draw on when presented with a word problem in maths. Using these problem-solving questions here are some suggested strategies you can empower your students with:
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A set of 40 MAB flashcards of random numbers between 100 and 10000.
A set of place value cards to help students explore and expand larger numbers.
A worksheet to use to consolidate student understanding of place value to the thousands.
Identify acute, right, obtuse, straight, reflex and revolution angles with this cut-and-paste sorting worksheet.
Piggy Bank Pigs are a fun, hands on way for students to learn each of the coins and how their values add up to a certain amount.
Lower Grade Desk Plates with the alphabet, number line and student's name on them.
Area of 2D Shapes - so many rules and formulas to remember!
A mathematics investigation about location, embedded in a real-world context.
Use these area and perimeter task cards in your maths lessons to give your students practice solving real-world word problems.
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The optimal reactive power dispatch problem optimizes the shunt capacitor bank installation in distribution systems, reducing power loss and also reducing the financial loss for the electricity market associated with power loss. Moreover, the sharing of both active and reactive power from different renewable energy sources like PV and wind in the form of distributed generation also contributes toward reducing power loss and improving the voltage profile of the system. But the installation and maintenance costs associated with these additional set-ups are rarely taken into consideration any optimization problem. This paper aims to reduce the power loss and improve the voltage profile of a radial distribution network with the integration of capacitor banks, PV, and wind energy sources, while taking into account the overall associated cost of each parameter during optimization. The problem is formulated as a novel cost minimization problem aiming to achieve the optimal settings for a life-long capacitor bank-PV-wind integrated distribution network with the least possible installation, operational, and maintenance costs while reducing its power loss significantly for a span of 20 years. The uncertain nature of PV and wind power output has been modeled using the beta probability distribution function and the Weibull probability distribution function, respectively. This unique proposed problem statement of the capacitor bank-PV-wind power integrated distribution network has been tested on the IEEE 33 and IEEE 141 bus systems and solved using the rock hyraxes swarm optimization (RHSO) algorithm. The results were compared with those from other nine well-established techniques, from which it was concluded that the RHSO algorithm has obtained optimal conditions for both systems to operate efficiently. The problem has also been tested on a practical 13-bus 33 kV distribution network in Maharashtra, India, to validate its performance on a practical system. The RHSO has successfully reduced the power loss to almost 17.48% w.r.t. the base case for the practical network while maintaining a minimum overall cost of $51,073,687.7582 for an entire life-span of 20 years.
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Department of Power Engineering, Jadavpur University, Salt Lake Campus, Kolkata, India
Tanmay Das & Kamal Krishna Mandal
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Mr. Tanmay Das carried out basic design and simulation work and prepared a draft paper. Dr. Ranjit Roy and Dr. Kamal Krishna Mandal participated in checking simulation work, results and discussions, and sequence of writing and helped to organize the manuscript. All authors read and approved the final manuscript.
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Das, T., Roy, R. & Mandal, K.K. Solving the cost minimization problem of optimal reactive power dispatch in a renewable energy integrated distribution system using rock hyraxes swarm optimization. Electr Eng (2024). https://doi.org/10.1007/s00202-024-02548-9
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Basic probabilities expressed as fractions. In math, probability measures the likelihood of an event occurring. In these basic probability worksheets, students determine the probability of certain events and express then as a fraction. Dice: Worksheet #1. Raffle: Worksheet #2. Cards: Worksheet #3.
Year 5 - Statistics & Probability. Standard 5.SP.1.1 - Practice finding the probability of simple events.. Included Skills: Chance • List outcomes of chance experiments involving equally likely outcomes and represent probabilities of those outcomes using fractions-commenting on the likelihood of winning simple games of chance by considering the number of possible outcomes and the consequent ...
Basic probability worksheets for beginners in 6th grade and 7th grade to understand the different type of events such as more likely, less likely, equally likely and so on. Balls in container. Identify suitable events. Mutually inclusive and exclusive events. Free probability worksheets for kids include odds, spinner problems, coins, deck of ...
Grade 5 Probability Worksheets - Worksheets aid in improving the problem-solving skills of students in turn guiding the kids to learn and understand the patterns as well as the logic of math faster. ... get to further their knowledge with skills like probability on a single coin, two coins, days in a week, months in a year, fair die, pair of ...
Students can get a fair idea on the probability questions which are provided with the detailed step-by-step answers to every question. Solved probability problems with solutions: 1. The graphic above shows a container with 4 blue triangles, 5 green squares and 7 red circles. A single object is drawn at random from the container.
Probability tells us how often some event will happen after many repeated trials. You've experienced probability when you've flipped a coin, rolled some dice, or looked at a weather forecast. Go deeper with your understanding of probability as you learn about theoretical, experimental, and compound probability, and investigate permutations, combinations, and more!
A two-digit number is written at random. Determine the probability that the number will be: a) an odd number. b) larger than 75. c) a multiple of 5. d) an even number smaller than 40. In a group of 30 students, there are 14 girls and 4 of them can speak French. 6 of the 16 boys can speak French.
This hands-on deck of probability problem cards allows students to work with numbers they are comfortable with, with opportunities to extend. More probability problems for your students to grapple with. The probability problems in this deck of cards are ideal for Year 5 NAPLAN revision and longer, more involved problem-solving projects.
Example: there are 5 marbles in a bag: 4 are blue, and 1 is red. What is the probability that a blue marble gets picked? Number of ways it can happen: 4 (there are 4 blues). Total number of outcomes: 5 (there are 5 marbles in total). So the probability = 4 5 = 0.8
Try to work out what your expected probability is, and then describe it using a fraction. Then the challenge is to roll your die 12, 24 or even 50 times, and see if your actual outcome matches the ...
A bag contains 3 green marbles, 5 blue marbles, and 8 red marbles and you ask a friend to pick one without looking. What is the probability that the marbles will be green? 9. You think of a number from the first twenty positive integers. What is the probability that the integer chosen will be divisible by 4? 10.
Introduce relevant contexts involving chance that have equally likely outcomes to then discuss the possible outcomes. For example: a coin toss: heads, tails. selecting a red card from a pack of 52 cards: 13 hearts and 13 diamonds. rolling an even number on a die: 2, 4 or 6. a spinner equally divided into four colours: red, blue, yellow, green.
8th grade probability questions. 5. Alice has some red balls and some black balls in a bag. Altogether she has 25 balls. Alice picks one ball from the bag. The probability that Alice picks a red ball is x and the probability that Alice picks a black ball is 4x. Work out how many black balls are in the bag. 6 6. 100 100.
Practice Questions. Previous: Direct and Inverse Proportion Practice Questions. Next: Reverse Percentages Practice Questions. The Corbettmaths Practice Questions on Probability.
Refer to ACARA work sample 11, 'Come in spinner', to assess students' understanding of probability through the task. Students list outcomes of chance experiments with equally likely outcomes and assign probabilities as a number from zero to one. This planning resource for Year 5 is for the topic of Conduct chance experiments.
Using these Year 5 maths worksheets will help your child learn to: apply their division facts up to 10x10 to answer related questions involving 10s and 100s. divide any whole number by a single digit. Divding by Multiples of 10 and 100 Worksheets. Year 5 (4th Grade) Long Division Worksheets.
Introduction to probability. Probability is a way of measuring, like length or area or weight or height. It measures the chance of a particular outcome occurring. You might have considered simple and familiar outcomes involving chance and described whether they are 'likely' or 'unlikely', with some being 'certain' or 'impossible'.
The examples cover variety of probability problems. Suggested Action. ... (Probability of none of them solving the problem) Probability of problem getting solved = 1 - (5/7) x (3/7) x (5/9) = (122/147) ... Find the probability that a leap year has 52 Sundays. Sol: A leap year can have 52 Sundays or 53 Sundays. In a leap year, there are 366 ...
Age range: 7-11. Resource type: Worksheet/Activity. File previews. docx, 510.4 KB. Three differentiated word problem worksheets about probability. Many cross topic links in questions of HA sheet, involving knowledge of angles, triangles etc. Hope it is useful as I struggled to find many resources with word problems for children to apply their ...
Multiplication and Division Word Problems Task Cards (2-Digit by 1-Digit) Use a range of strategies to solve 2-digit by 1-digit multiplication and division problems that exceed the facts of the 12 times tables. Slide PDF. Year s 4 - 5. Plus Plan.
This set of problem-solving questions has been designed to support teachers when teaching students about problem-solving in mathematics. It provides students with the opportunity to work through 20 maths word problems, identifying the important information and how they can work it out using a variety of methods. An answer sheet has been included.
Detailed Lesson Plan in Mathematics 5 - Free download as Word Doc (.doc / .docx), PDF File (.pdf), Text File (.txt) or read online for free. The document provides a detailed lesson plan for a mathematics lesson on experimental probability for 5th grade students. The lesson objectives are to identify probability through experimental results, perform experiments to find probabilities and list ...
Solve probability word problems step by step probability-problems-calculator. en. Related Symbolab blog posts. Middle School Math Solutions - Inequalities Calculator.
Art of Problem Solving AoPS Online. Math texts, online classes, and more for students in grades 5-12. Visit AoPS Online ‚ Books for Grades 5-12 ...
The uncertain nature of PV and wind power output has been modeled using the beta probability distribution function and the Weibull probability distribution function, respectively. This unique proposed problem statement of the capacitor bank-PV-wind power integrated distribution network has been tested on the IEEE 33 and IEEE 141 bus systems and ...